Double数据类型有问题，返回1.00而不是1.8

Question

我正在为我的大学做一个项目，到目前为止，代码运行得很好，除了当一个程序试图计算所有输入的平均值时，它总是给出错误的答案。 前任： 测试输入： 3. -4 5. 12 -7 0（退出循环）

结果->； 总数：9 柜台：5 平均值=1.0？应该是1.8

如果有人能帮忙，请给我一些建议

public static void main(String[] args) 
{
    Scanner sc = new Scanner(System.in);
    int counter = 0;

    int intInput;
    int intLargest;
    int intSmallest;
    int intEven = 0;
    int intOdd = 0;
    int intSum = 0;
    String strMessage = "Enter a series of value (0 to quit)";    


    System.out.print(strMessage);
    System.out.println();        

   System.out.print("Enter Integer value?" + "\n");
   intInput = sc.nextInt();

        intLargest = intInput;
        if (intLargest == 0)
        {
            intLargest = 0;
        }
        else
        {
            intLargest = intInput;
        }
        /////////////////////////////////////////////////////////////

        intSmallest = intInput;
        if (intSmallest == 0)
        {
            intSmallest = 0;
        }
        else
        {
            intSmallest = intInput;
        }            



    while(intInput != 0)
    { 
    {            
      if (intInput > intLargest)
      {
          intLargest = intInput;
      }//Get the largest value        
      else if (intInput < intSmallest)
      {
          intSmallest = intInput;
      }//Get the smallest value


      if ((intInput%2) == 0)
      {
          intEven++;
      }//Get number of Even value
      else if ((intInput%2) != 0)
      {
          intOdd++;
      }//Get number of Odd value
    }


      intSum = intSum + intInput;        
      intInput = sc.nextInt();
      counter++;
    }

/******************************************************************/

    double doubleAvg = 0;

    if (counter > 0)
    {
        doubleAvg = intSum / counter;
    }     

/***************************************************/

    System.out.println();
    System.out.print("Smallest = " + intSmallest +"\n");        
    System.out.print("Largest = " + intLargest + "\n");
    System.out.print("Total Entered = " + counter + "\n");        
    System.out.print("Even Number = " + intEven + "\n");
    System.out.print("Odd Number = " + intOdd + "\n");
    System.out.print("Average = " + doubleAvg + "\n");
    System.out.print("SUM: " + intSum + "\n");
}

}

Answer 1

intSum和counter都被声明为int。在用int除以int的情况下，结果也是int。所以除法的结果是1，然后它被转换成double，得到1.0。要获得正确的结果，请将intSum声明为double