java使用xpath更新xml文档
您好这是我的xml文档:
<city>
<beirut>
<restaurant>
<name>sada</name>
</restaurant>
</beirut>
<jbeil>
<restaurant>
<name>toto</name>
<rating>4.3/5</rating>
</restaurant>
<restaurant>
<name>jojo</name>
<rating>4.3/5</rating>
</restaurant>
</jbeil>
<sour>
<restaurant>
<name>sada</name>
</restaurant>
</sour>
</city>
我想使用xpath和netbeans将jbeil中“jojo”餐厅的评级从4.3/5更新为4.5/5请帮助
该代码给出了评级
try {
File inputFile = new File("src/xpath/josephXml.xml");
DocumentBuilderFactory dbFactory
= DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder;
dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(inputFile);
doc.getDocumentElement().normalize();
XPath xPath = XPathFactory.newInstance().newXPath();
String expression = "/City/Jbeil/Restaurant";
NodeList nodeList = (NodeList) xPath.compile(expression).evaluate(doc, XPathConstants.NODESET);
for (int i = 0; i < nodeList.getLength(); i++) {
Node nNode = nodeList.item(i);
System.out.println("\nCurrent Element :"
+ nNode.getNodeName());
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
System.out.println("rating : "
+ eElement
.getElementsByTagName("rating")
.item(0)
.getTextContent());
我只想更新jbeil餐厅的评级,那里的名字是“jojo”,请帮忙
# 1 楼答案
这是一种可能的XPath,可以在
jbeil
市找到名为jojo
的餐厅,然后返回相应的rating
元素:请注意,XML&;XPath是区分大小写的,所以我在上面的XPath中使用了所有小写字符来匹配这个问题中发布的XML
我对Java知之甚少,但在互联网上快速搜索*建议如下:
*)how to modify xml tag specific value in java?