java中将字符串解析为布尔值的变量

Question

我有以下简单的销售计划，但在围绕该计划创建重启循环时遇到了困难。我的主要问题是将布尔值从字符串转换为布尔值类型，我在Eclipse中遇到了一个错误，错误是“对于布尔值类型，parseBoolean（string）方法未定义”

然而，我在顶部定义了一个布尔变量，boolean tryAgain=false

由于某些原因，我无法设置用户输入扫描仪，使其在没有错误的情况下获取真值或假值。当我试图将下一行从用户强制转换为布尔值时，最后一行出现了错误

import java.util.Scanner;
public class Sales {
    public static void main(String args[]) {

        String item1, item2, item3;                 //Three vars for items
        double price1, price2, price3;              //Three vars for price
        int quantity1, quantity2, quantity3;        //Three vars for quantity
        Scanner userInput = new Scanner(System.in); //Creates scanner for user input
        double sum;                                 //var for total before tax
        double tax;                                 //var for tax
        double total;                               //var for total with tax
        double tax_total;                           //var to calculate tax
        boolean tryAgain = true;                    //boolean for try again loop to restart program

        // First set of inputs

        while (tryAgain) {

            System.out.println("Please enter the first item: ");
            item1 = userInput.nextLine();
            System.out.println("Please enter the price of the first item: ");
            price1 = userInput.nextDouble();
            System.out.println("Please enter the quantity purchased: ");
            quantity1 = userInput.nextInt();

            // Second set of inputs

            System.out.println("Please enter the second item: ");
            item2 = userInput.next(); 
            System.out.println("Please enter the price of the second item: ");
            price2 = userInput.nextDouble();
            System.out.println("Please enter the quantity purchased: ");
            quantity2 = userInput.nextInt();

            // Third set of inputs

            System.out.println("Please enter the third item: ");
            item3 = userInput.next(); //skipping over item 2.  Why?
            System.out.println("Please enter the price of the third item: ");
            price3 = userInput.nextDouble();
            System.out.println("Please enter the quantity purchased: ");
            quantity3 = userInput.nextInt();

            System.out.println("Please enter the sales tax rate: ");            //Prompt user for tax rate
            tax = userInput.nextDouble();

            //Print line item totals

            System.out.println("Line item totals");
            System.out.println("____________________");
            System.out.println("Item 1: " + item1 + "\t" + "$" + price1);
            System.out.println("Item 2: " + item2 + "\t" + "$" + price2);
            System.out.println("Item 3: " + item3 + "\t" + "$" + price3);
            System.out.println();

            //Process final output for display

            sum = price1 + price2 + price3;
            total = (sum * tax) + sum;
            tax_total = tax * sum;
            System.out.println("Total cost(no tax):\t" + "$" + sum);                    //display total cost witout tax
            System.out.println("Total tax(" + tax + " rate): \t" + "$" + tax_total);    //display total tax
            System.out.println("Total cost(with tax):\t" + "$" + total);                //display total with tax
            System.out.println();
            System.out.println("Program created by James Bellamy");

            System.out.println("Do you want to run the program again? (True or False)");

            tryAgain = Boolean.parseBoolean(userInput.nextLine());

        }




    }

}

Answer 1

它给您带来麻烦的原因是，当用户输入一个double，然后点击enter时，两个东西刚刚被输入——double和一个“换行符”，即\n

您正在调用的方法“nextDouble（）”只读取double，这将在输入流中保留换行符。但是调用nextLine（）确实会读取换行符，这就是为什么在代码运行之前必须调用nextLine（）

将这一行添加到最后一行之前

userInput.nextLine();

Answer 2

Scanner支持nextBoolean()。只要使用它：

tryAgain = userInput.nextBoolean()