java查找学生的最小值和平均值（如果存在），并显示学生的姓名

Question

public static void main(String[] args) {
    // TODO code application logic here

   int[] age = new int []{21,20,19,18,18,};
   String name [] = {"sofia","maria","john","Petra","mark"};
  int sum = 0;
  int avg;
  int min=age[0];
  int i;
  int counter=0;
  for(i=0;i<age.length;i++){
  if(age[i]<min ) {
            min=age[i];

  }




  avg= sum/age.length;

  System.out.println("the avarage of all Students are :"+avg);
  System.out.println("the minimum age of all Students : "+min);


    }
  for(i=0;i<age.length;i++){
  if (age[i] == min ) {
          System.out.println("the minimum age of all Students  : "+name[i]); 
        }

  }
}

} //我们有学校的（年龄）和（姓名）——>；查找“john”是学校里打印“他的年龄”的名字如果有多个“john”打印所有年龄的学生都叫“john”有人能帮我解决这个问题吗

Answer 1

尝试添加一个for循环来计算年龄总和，如下所示：

    for(i=0;i<age.length;i++){
        sum+=age[i];
      }

把下面这个方块从for循环中取出：

  avg= sum/age.length;
  System.out.println("the avarage of all Students are :"+avg);
  System.out.println("the minimum age of all Students : "+min);

像这样：

  public static void main(String[] args) {
    // TODO code application logic here

   int[] age = new int []{21,20,19,18,18,};
   String name [] = {"sofia","maria","john","Petra","mark"};
  int sum = 0;
  int avg;
  int min=age[0];
  int i;
  int counter=0;
  for(i=0;i<age.length;i++){
  if(age[i]<min ) {
     min=age[i];

   }
 }
  for(i=0;i<age.length;i++){
        sum+=age[i];
      }

  avg= sum/age.length;
  System.out.println("the avarage of all Students are :"+avg);
  System.out.println("the minimum age of all Students : "+min);
  for(i=0;i<age.length;i++){
  if (age[i] == min ) {
          System.out.println("the minimum age of all Students  : "+name[i]); 
        }

     }
    }
   } 

输出：

 the avarage of all Students are :19
 the minimum age of all Students : 18
 the minimum age of all Students  : Petra
 the minimum age of all Students  : mark