使用php集成和线程在安卓中注册java用户

Question

我的代码有问题，无法找出问题所在 我正在尝试制作一份注册表，并将用户名和密码提交到数据库 用户名和密码已成功存储在数据库中，但问题是我无法测试它们是否已插入。 我有一个反应测试仪

if(response.equalsIgnoreCase("1")){

            dialog.dismiss();
                showAlert();    
        }

但问题是执行dialog.dismiss();而不执行showAlert();

这是我的RegisterActivity.java的完整代码

Button b;
EditText et,pass;
TextView tv;
HttpPost httppost;
StringBuffer buffer;
HttpResponse response;
HttpClient httpclient;
List<NameValuePair> nameValuePairs;
ProgressDialog dialog = null;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_register);

    b = (Button)findViewById(R.id.button1);  
    et = (EditText)findViewById(R.id.username);
    pass= (EditText)findViewById(R.id.password);

    b.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View v) {
            dialog = ProgressDialog.show(RegisterActivity.this, "", 
                    "Validating user...", true);

             new Thread(new Runnable() {
                    public void run() {
                        Register();
                    }
                  }).start();               
        }
    });

}

void Register(){
    try{            

        httpclient=new DefaultHttpClient();
        httppost= new HttpPost("http://192.168.1.112/RegisterConnectNow.php"); // make sure the url is correct.
        //add your data
        nameValuePairs = new ArrayList<NameValuePair>(2);
        // Always use the same variable name for posting i.e the 安卓 side variable name and php side variable name should be similar, 
        nameValuePairs.add(new BasicNameValuePair("username",et.getText().toString().trim()));  // $Edittext_value = $_POST['Edittext_value'];
        nameValuePairs.add(new BasicNameValuePair("password",pass.getText().toString().trim())); 
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
        //Execute HTTP Post Request
        response=httpclient.execute(httppost);
        // edited by James from coderzheaven.. from here....
        ResponseHandler<String> responseHandler = new BasicResponseHandler();

        final String response = httpclient.execute(httppost, responseHandler);


        if(response.equalsIgnoreCase("1")){

            dialog.dismiss();
                showAlert();    
        }else {
            dialog.dismiss();
            showAlert();
        }

    }catch(Exception e){

        dialog.dismiss();
    }

}
public void showAlert(){
    new AlertDialog.Builder(this)
    .setTitle("OK")
    .setMessage("OK")
    .setPositiveButton(安卓.R.string.yes, new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int which) { 
            // continue with delete
        }
     })
    .setNegativeButton(安卓.R.string.no, new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int which) { 
            // do nothing
        }
     })
    .setIcon(安卓.R.drawable.ic_dialog_alert)
     .show();
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.register, menu);
    return true;
}

@Override
public boolean onOptionsItemSelected(MenuItem item) {
    // Handle action bar item clicks here. The action bar will
    // automatically handle clicks on the Home/Up button, so long
    // as you specify a parent activity in AndroidManifest.xml.
    int id = item.getItemId();
    if (id == R.id.action_settings) {
        return true;
    }
    return super.onOptionsItemSelected(item);
}
public void displayToast(String s){
     Toast.makeText(getApplicationContext(), s, Toast.LENGTH_SHORT).show();
}

这是php脚本

DatabaseConnectNow.php

    <?php
$hostname_localhost ="localhost";
$database_localhost ="users";
$username_localhost ="root";
$password_localhost ="";
$localhost = mysql_connect($hostname_localhost,$username_localhost,$password_localhost)
or
trigger_error(mysql_error(),E_USER_ERROR);

mysql_select_db($database_localhost, $localhost);
?>

RegisterConnectNow.php

<?php
require_once 'DatabaseConnectNow.php';
$username = $_POST['username'];
$password = $_POST['password'];
$query_search = "select * from userstable where username = '".$username."'";
$query_exec = mysql_query($query_search) or die(mysql_error());
$rows = mysql_num_rows($query_exec);

 if($rows == 0) { 
 $query = "INSERT INTO userstable (username,password)
                    VALUES ('$username', '$password')";

            mysql_query($query);

            echo "1";
 }
 else  {
    echo "2"; 
}
?>

所以我正在测试响应是否为1，然后它应该显示对话框，我试着显示一个吐司，同样的事情是什么都没有显示，我感觉这与线程有关

谢谢你的帮助