如何检查循环结束，三轮检查java

Question

我是java新手，正在尝试为解析的数据构建游戏流程

1. 游戏每轮三次，因此如果ArrayList中有更多场景，游戏将提示用户继续玩
2. 如果只有三种情况，游戏将直接结束，而不提示用户继续
3. 如果场景数不除以3。例如，10，游戏没有场景，直接结束游戏

任何帮助或暗示都将不胜感激。谢谢!

我试过这样做：

public void interactConfig (ArrayList<Scenario> scenarios, Audit audit) throws IOException {

    ArrayList<Character> passengers = new ArrayList<Character>(); // create new reference arrayList
    ArrayList<Character> pedestrians = new ArrayList<Character>(); // otherwise, it will be all the data

    for (int i = 1; i < scenarios.size() + 1; i++) {

        Scenario s = scenarios.get(i-1);
        passengers = s.getPassengers();
        pedestrians = s.getPedestrians();
        System.out.println(s.toString());
        audit.addRun();
    
        System.out.println("Who should be saved? (passenger(s) [1] or pedestrian(s) [2])");
        String command = in.nextLine();
        
        // want to check if the game reaches the end
        // or run out of the scenarios, but failed
        if (i == scenarios.size() + 1) {
            
            decisionCalculate(command, audit, passengers, pedestrians);               
            System.out.println(audit.toString());           
            audit.printStatistic();

        }

        // three scenarios per round is perfect
        if (i != 0 && i % 3 == 0) {

            decisionCalculate(command, audit, passengers, pedestrians);
            System.out.println(audit.toString());           
            audit.printStatistic();

            System.out.println("Would you like to continue? (yes/no)");
            playAgain = in.nextLine();
            
            if (playAgain.equals("yes"))
                continue;
            else 
                break;
            
        } 
        
        // if the numbers of scenarios is not yet three times, the game keeps going
        else if (i == 0 && (i % 3) != 0) {

            decisionCalculate(command, audit, passengers, pedestrians);
            
        }
    }
}

Answer 1

如果使用i % 3 == 0，它将显示第一轮的四个场景（0、1、2、3）。这就是我为什么设定从1开始

因此，为了降低复杂性并提高可读性，我选择使用另一个名为numScenario的变量来表示场景的实际数量，并返回int i = 0。然后，使用模来进行流量控制就更容易了

我喜欢这样：

public void interactConfig (ArrayList<Scenario> scenarios, Audit audit) throws IOException {

    ArrayList<Character> passengers = new ArrayList<Character>(); // create new reference arrayList
    ArrayList<Character> pedestrians = new ArrayList<Character>(); // otherwise, it will be all the data

    for (int i = 0; i < scenarios.size(); i++) {

        int numScenario = i + 1;

        Scenario s = scenarios.get(i);
        passengers = s.getPassengers();
        pedestrians = s.getPedestrians();
        System.out.println(s.toString());
        audit.addRun();
    
        System.out.println("Who should be saved? (passenger(s) [1] or pedestrian(s) [2])");
        String command = in.nextLine();

        // if it reaches the last round, it will be this scenario
        if (numScenario % 3 == 0 && numScenario == scenarios.size()) {
            
            decisionCalculate(command, audit, passengers, pedestrians);

        } 
        // if it's not the end the ArrayList, will be this one
        else if (numScenario % 3 == 0 && numScenario != scenarios.size()) {

            decisionCalculate(command, audit, passengers, pedestrians);

            System.out.println(audit.toString());           
            audit.printStatistic();

            System.out.println("Would you like to continue? (yes/no)");
            playAgain = in.nextLine();
            
            if (playAgain.equals("yes"))
                continue;
            else 
                break;
        }
        // other scenarios situation
        else if (numScenario % 3 != 0) {               

            decisionCalculate(command, audit, passengers, pedestrians);
            
        }
        
    }